<?xml version="1.0" encoding="UTF-8"?>
<response><exercises><id>63809a2c-0b5e-4f87-a696-bd16ebc92a73</id><unit_id>49e0ceb4-d55c-4141-a177-7b718c0c8dff</unit_id><language_id>6c89a17a-24f3-4809-bf53-6c9b648a6173</language_id><number>1.3.4.7</number><statement>&lt;p&gt;Calcular el valor de les funcions trigonomètriques (sinus, cosinus i tangent) de $$x=\dfrac{5\pi}{6}$$ rad.&lt;/p&gt;</statement><development>&lt;p&gt;L'angle $$\dfrac{5\pi}{6}$$ és un angle del segon quadrant, és a dir, $$\dfrac{\pi}{2} &lt; \dfrac{5\pi}{6} &lt; \pi$$, per tant tenim:
$$$\sin(x)=\sin(\dfrac{5\pi}{6})=\sin(\pi-\dfrac{5\pi}{6})=\sin(\dfrac{\pi}{6})=\dfrac{1}{2}$$$&lt;/p&gt;
&lt;p&gt;$$$\cos(x)=\cos(\dfrac{5\pi}{6})=-\cos(\pi-\dfrac{5\pi}{6})=-\cos(\dfrac{\pi}{6})=-\dfrac{\sqrt{3}}{2}$$$&lt;/p&gt;
&lt;p&gt;$$$\tan(x)=\tan(\dfrac{5\pi}{6})=-\tan(\pi-\dfrac{5\pi}{6})=-\tan(\dfrac{\pi}{6})=-\dfrac{\sqrt{3}}{3}$$$&lt;/p&gt;</development><solution>&lt;p&gt;$$\sin(x)=\dfrac{1}{2}$$&lt;/p&gt;
&lt;p&gt;$$\cos(x)=-\dfrac{\sqrt{3}}{2}$$&lt;/p&gt;
&lt;p&gt;$$\tan(x)=-\dfrac{\sqrt{3}}{3}$$&lt;/p&gt;</solution><created>18/7/16 11:44</created><modified>18/7/16 11:44</modified></exercises></response>
