Problems from Elements of a square root and calculation step by step

Development:

We group the digits two by two and $$47.19.69$$ is obtained in the radicand. We look for a number that, when squared, gives $$47$$. The closest number is $$6$$ because $$6\cdot6 = 36$$.

47.19.69	6
	6·6=36

This result is subtracted from $$47$$ and the following digits $$(19)$$ are moved down. We also separate the last number.

47.19.69	6
-36	6·6=36
111.9

Then write the double of $$6$$, which is $$12$$. We divide $$111$$ by $$12$$, to obtain the number that it is necessary to add and to multiply. In this case it is $$8$$.

It is subtracted and the following group of two digits are moved down and the last digit is separated.

47.19.69	68
-36	6·6=36
111.9	6·2=12
-1024	128·8=1024
956.9

We repeat the previous step.

The double of $$68$$ is written below, $$136$$. Divide $$956$$ by $$136$$, to obtain the number that it is necessary to add and to multiply. In this case it is $$7$$, which must be added to the first line.

Operating the remainder is zero, therefore, the first line is taken and that number is the root.

47.19.69	687
-36	6·6=36
111.9	6·2=12
-1024	128·8=1024
956.9	68·2=136
-9569	1367·7=9569
0

Solution:

$$\sqrt{471969}=687$$

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