Is this function continuous $$f(x)=+\sqrt{x-3}$$?

See development and solution

### Development:

Radical functions are continuous within their domain. In this case

$$$x-3 \geq 0$$$ $$$x\geq3$$$ $$$\Rightarrow D(f_x)=[3,+\infty)$$$

### Solution:

Therefore $$f(x)$$ is continuous in $$[3,+\infty)$$.