Solve the following expressions:
a) $$9^x=2$$
b) $$3+(5-2)^y-1=\dfrac{25}{5}$$
See development and solution
Development:
a) $$9^x=2 \Rightarrow x=log_9 2$$
b) $$3+(5-2)^y-1=\dfrac{25}{5}$$
Because of the hierarchy of the operations we firstly do what is in brackets: $$(5-2)=3$$
and then the quotients: $$\dfrac{25}{5}=5$$
Re-writing and operating: $$3+3^y-1=5 \Rightarrow 3^y=3 \Rightarrow y=log_3 3=1$$
Solution:
a) $$x=log_9 2$$
b) $$y=1$$