Determine the vector equation of a plane that goes through point $$A = (1, 0, 3)$$ and has as director vectors $$\overrightarrow{u}= (-1, 3, 2)$$ and $$\overrightarrow{v}= (2, 1, 0)$$.
See development and solution
Development:
The vector equation is: $$(x, y, z) = (1, 0, 3) + k\cdot (-1, 3, 2) + m \cdot(2, 1, 0)$$
Solution:
$$(x, y, z) = (1, 0, 3) + k\cdot (-1, 3, 2) + m \cdot(2, 1, 0)$$