# Problems from Inequations with two variables

Solve the following inequations and give the region in the plane where they are satisfied:

1. $$y-3x > 2$$

2. $$2(x-y)-3(y+2) < 2x+1$$

3. $$\dfrac{-x+4y}{3}-x \geqslant 2y+x$$
See development and solution

### Development:

We are going to solve three inequations. We will give the expression of the inequation as $$y < ax+b$$ and will say what points of the plane we take.

1. $$y-3x > 2 \Rightarrow y > 3x -2$$. The solution region is above the straight line (we have an inequality of the type $$>$$).

2. $$2(x-y)-3(y+2) < 2x+1 \Rightarrow 2x-2y-3y-6 < 2x+1 \Rightarrow$$ $$\Rightarrow 2x-2x-6-1 < 5y \Rightarrow y > -\dfrac{7}{5}$$. The solution region is above the straight line.

3. $$\dfrac{-x+4y}{3}-x\geqslant 2y+x \Rightarrow \dfrac{-x+4y-3x}{3} \geqslant 2y+x \Rightarrow$$ $$\Rightarrow -x+4y-3x \geqslant 6y+3x \Rightarrow -x-3x-3x \geqslant 6y-4y \Rightarrow y \leqslant \dfrac{-7}{2}x$$. The solution region is below the straight line, taking also the line points.

### Solution:

1. $$y > 3x -2 \Rightarrow$$ Points above de line $$y-3x = 2$$ without the points in the line.

2. $$y > -\dfrac{7}{5} \Rightarrow$$ Points above de line $$y = -\dfrac{7}{5}$$ without the points in the line.

3. $$y \leqslant \dfrac{-7}{2}x \Rightarrow$$ Points below de line $$y = \dfrac{-7}{2}x$$ with the points in the line.
Hide solution and development