# Problems from Divisors and multiples of a number

Look at for the divisors of the numbers $$35, 22, 10$$ and $$42$$.

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### Development:

$$35 \div 1=35 \\ 35 \div 5=7 \\ 35 \div 7=5 \\ 35 \div 35=1$$

$$22 \div 1=22 \\ 22 \div 2=11 \\ 22 \div 11=2 \\ 22 \div 22=1$$

$$10 \div 1=10 \\ 10 \div 2=5 \\ 10 \div 5=2 \\ 10 \div 10=1$$

$$42 \div 1=42 \\ 42 \div 2=24 \\ 42 \div 3=14 \\ 42 \div 6=7 \\ 42 \div 7=6 \\ 42 \div 14=3 \\ 42 \div 24=2 \\ 42 \div 42=1$$

### Solution:

The divisors of $$35$$ are the following numbers: $$1, 4, 7$$ and $$35$$.

The divisors of $$22$$ are the following numbers: $$1, 2, 11, 22$$.

The divisors of $$10$$ are the following numbers: $$1, 2, 5, 10$$.

The divisors of $$42$$ are the following numbers: $$1, 2, 3, 6, 7, 14, 24$$ and $$42$$.

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Look for three multiples of the number $$3$$, four multiples of the number $$5$$ and three multiples of $$3$$ and $$2$$ at the same time.

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### Development:

$$3\times2=6 \ \ 3\times3=9 \ \ 3\times4=12$$

$$5\times2=10 \ \ 5\times3=15 \ \ 5\times4=20 \ \ 5\times5=25$$

$$3\times2=6 \ \ 3\times2\times2=12 \ \ 3\times2\times3=18$$

### Solution:

The numbers $$6, 9$$ and $$12$$ are multiples of the number $$3$$.

The numbers $$10, 15, 20$$ and $$25$$ are multiples of $$5$$.

The numbers $$6, 12$$ and $$18$$ are multiples common of $$2$$ and $$3$$.

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