Problems from Simplification in expressions with factorials

Calculate the value of: $$\dfrac{8!\cdot3!}{9!\cdot4!}$$

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Development:

$$$\dfrac{8!\cdot3!}{9!\cdot4!}=\dfrac{\cancel{8!}\cdot\cancel{3!}}{9\cdot\cancel{8!}\cdot4\cdot\cancel{3!}}=\dfrac{1}{9\cdot4}=\dfrac{1}{36}$$$

Solution:

$$\dfrac{1}{36}$$

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