Given $$f (x) = x - 1$$ and $$g (x) =\dfrac{x^2}{1-x}$$, find $$(f \circ g) (x)$$.

See development and solution

### Development:

$$(f \circ g) (x)=f(g(x))=g(x)-1=\dfrac{x^2}{1-x}-1=\dfrac{x^2-1+x}{1-x}=\dfrac{x^2+x-1}{1-x}$$

### Solution:

$$(f \circ g) (x)=\dfrac{x^2+x-1}{1-x}$$