 Write in degrees and in radians the range of an angle of any equilateral triangle.
 Write in degrees and radians three full rotations to the circumference unit.
Development:

We know that the sum of all angles in a triangle is $$180th^\circ$$, since an equilateral triangle has three equal angles what we must write is $$60^\circ$$. Let's now convert this into radians by means of the conversion factor that transforms from degrees to radians: $$$60^\circ \cdot \dfrac{2\pi \ \mbox{radians}}{360^\circ}=\dfrac{60\cdot 2\pi}{360}\mbox{radians} = \dfrac{\pi}{3} \mbox{radians} $$$

We know that a full rotation is $$360^\circ$$, therefore three full rotations will be $$3 \cdot 360^\circ$$ giving a total of $$1080^\circ$$. But, on the other hand, we also know that a full rotation corresponds to the total longitude of the circumference which, in this case, is $$2\pi$$. If there are three turns, there are $$3 \cdot 2\pi$$ which equals $$6\pi$$ radians. If we prefer to do it by means of a conversion factors then: $$$1080^\circ \cdot \dfrac{2\pi \ \mbox{radians}}{360^\circ}=\dfrac{1080\cdot 2\pi}{360}\mbox{radians} = 6\pi \ \mbox{radians} $$$
Solution:
 $$60^\circ = \dfrac{\pi}{3} \mbox{radians} $$
 $$1080^\circ = 6\pi \ \mbox{radians} $$